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Multi-digit multiplication step by step: partial products vs the standard algorithm

Grades 4–55 min read

Multi-digit multiplication step by step: partial products vs the standard algorithm: 247 × 36 = 8892, worked on a MathPad-style grid.12124247×361482×6+7410×38892MathPad
Multi-digit multiplication step by step: partial products vs the standard algorithm: 247 × 36 = 8892, worked on a MathPad-style grid.

If your fourth grader comes home drawing boxes to multiply 46 × 23, you are seeing partial products. If you learned to multiply with carries stacked above the top number, that is the standard algorithm. Both are correct, and they are closer than they look.

This guide shows each method on the same problem, explains why schools often teach the boxes first, and walks through the steps where kids usually slip.

What your child needs first

Two things make multi-digit multiplication much easier.

  • Times tables up to 9 × 9. Every step comes back to a single-digit fact. If 7 × 8 still takes a while, everything else slows down. Our post on times tables practice that sticks has a plan.
  • Multiplying by tens. They should know that 40 × 20 is 4 × 2 with two zeros on the end, so 40 × 20 = 800, and be able to say why.

Method one: partial products (the box method)

Partial products split each number into tens and ones, multiply every piece by every piece, and add it all up. For 46 × 23, split 46 into 40 and 6, and 23 into 20 and 3.

Draw a box with two columns (40 and 6) and two rows (20 and 3). Fill each square:

  • 40 × 20 = 800
  • 6 × 20 = 120
  • 40 × 3 = 120
  • 6 × 3 = 18

Then add the four pieces: 800 + 120 + 120 + 18 = 1058.

The box is a picture of area. A rectangle 46 wide and 23 tall, cut into four smaller rectangles. That is why teachers like it: a child can see that every part of one number gets multiplied by every part of the other.

Method two: the standard algorithm

The standard algorithm does the same multiplying, but packs it into fewer lines. You multiply the top number by one digit of the bottom number at a time.

Start with a one-digit multiplier

Practice with a single digit on the bottom first, like 238 × 4.

  1. 1Ones: 8 × 4 = 32. Write 2, carry 3 above the tens.
  2. 2Tens: 3 × 4 = 12, plus the carried 3 makes 15. Write 5, carry 1 above the hundreds.
  3. 3Hundreds: 2 × 4 = 8, plus the carried 1 makes 9. Write 9.
  4. 4The answer is 952.
Worked example238 × 4 = 952
Multiply first, then add the carry. Never the other way around.
Every step, the way the pad explains it
  1. Multiply 4 × 8 = 32. Write 2, carry 3.
  2. Multiply 4 × 3 = 12, plus the carried 3 = 15. Write 5, carry 1.
  3. Multiply 4 × 2 = 8, plus the carried 1 = 9. Write 9.

Then a two-digit multiplier

Now 46 × 23. Multiply 46 by the 3 first: 46 × 3 = 138. That is the first line.

Next, multiply 46 by the 2. But that 2 is in the tens place, so it is really 20. Write a 0 in the ones place of the second line first, as a placeholder. Then 46 × 2 = 92 goes in front of it, giving 920.

Add the two lines: 138 + 920 = 1058. Same answer as the box.

Worked example46 × 23 = 1058
Line one is 46 × 3. Line two is 46 × 20, which is why it starts with a 0.
Every step, the way the pad explains it
  1. Multiply 3 × 6 = 18. Write 8, carry 1.
  2. Multiply 3 × 4 = 12, plus the carried 1 = 13. Nothing left to multiply, so write the whole 13.
  3. Now multiply by the tens digit, 2. The placeholder 0 is already there. Multiply 2 × 6 = 12. Write 2, carry 1.
  4. Multiply 2 × 4 = 8, plus the carried 1 = 9. Write 9.
  5. Add the ones: 8 + 0 = 8. Write 8.
  6. Add the tens: 3 + 2 = 5. Write 5.
  7. Add the hundreds: 1 + 9 = 10. Write 0, carry 1.
  8. Nothing left to add in the thousands place — the carried 1 drops straight down into the answer.

How the two methods connect

Look at the box again. The bottom row of the box was 40 × 3 and 6 × 3, which is 120 + 18 = 138. That is the first line of the standard algorithm.

The top row was 40 × 20 and 6 × 20, which is 800 + 120 = 920. That is the second line.

So the standard algorithm is partial products with each row of the box already added up. Showing your child this link is one of the most useful things you can do. It turns two separate tricks into one idea.

A bigger example: 247 × 36

Once two-digit problems are comfortable, try three digits by two. First line: 247 × 6 = 1482. Second line: 247 × 30 = 7410. Add them: 1482 + 7410 = 8892.

Worked example247 × 36 = 8892
The second partial product starts with a 0 because the 3 means 30.
Every step, the way the pad explains it
  1. Multiply 6 × 7 = 42. Write 2, carry 4.
  2. Multiply 6 × 4 = 24, plus the carried 4 = 28. Write 8, carry 2.
  3. Multiply 6 × 2 = 12, plus the carried 2 = 14. Nothing left to multiply, so write the whole 14.
  4. Now multiply by the tens digit, 3. The placeholder 0 is already there. Multiply 3 × 7 = 21. Write 1, carry 2.
  5. Multiply 3 × 4 = 12, plus the carried 2 = 14. Write 4, carry 1.
  6. Multiply 3 × 2 = 6, plus the carried 1 = 7. Write 7.
  7. Add the ones: 2 + 0 = 2. Write 2.
  8. Add the tens: 8 + 1 = 9. Write 9.
  9. Add the hundreds: 4 + 4 = 8. Write 8.
  10. Add the thousands: 1 + 7 = 8. Write 8.

Estimate first: 247 is about 250 and 36 is about 40, and 250 × 40 = 10000. The real answer should be a bit under that, because we rounded both numbers up. 8892 fits.

Where kids usually go wrong

  • Forgetting the placeholder zero. Without it, the second line shifts right and the answer is far too small. For 46 × 23 you get 138 + 92, which is nowhere near the estimate.
  • Adding the carry before multiplying. In 238 × 4, the tens step is 3 × 4 then add 3, not (3 + 3) × 4.
  • Mixing up carries from the two lines. On paper, cross out the carries from the first line before starting the second, so old carries do not get added in again.
  • Adding the partial products carelessly. The multiplying can be perfect and the final addition still slips. It is regular column addition with carrying, so the same care applies.

Which method should my child use?

Whichever one their teacher is asking for right now. Many schools teach partial products first and move to the standard algorithm in fourth or fifth grade. If your child is still on the box method, there is no rush. Understanding why it works is what makes the standard algorithm stick later.

If you want a quick reference, the multi-digit multiplication practice page sums up the steps and mistakes on one screen.

On the MathPad pad, multiplication is laid out in the standard form with a row for each partial product and the placeholder zero already in place. Carries are optional boxes, the way most kids write them small, and Practice mode can turn every real carry into a box the pad points to, with a hint, for kids who keep dropping them.

Questions parents ask

Why do schools teach partial products instead of the old way?
Partial products show what each digit is worth, so children understand why the steps work. Most schools still teach the standard algorithm too, usually after partial products.
Why do you put a zero on the second line?
Because the second digit of the bottom number is in the tens place. Multiplying by 2 tens is the same as multiplying by 20, and the zero shows that.

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